Verilog Code For 8 Bit Parallel In Serial Out Shift Register

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Verilog Code For 8 Bit Parallel In Serial Out Shift Register

Here is the Xilinx Circuit Design Library documentation on Serial Input Shift Register. It’s section See also the UG1371 white paper, 8-Bit Parallel-In/Serial-Out Shift Registers.
The Xilinx configuration uses SISR (Serial In, Parallel Out Shift Register).
If you are going to use the SISR module with other module types, make sure to follow the Xilinx instruction reference, where FIFO is specified as the output with Xilinx FIFO type. If you didn’t follow the Xilinx instruction reference, you must fix your FIFO to the right type.
module bis_sicir #(parameter width = 1,
parameter n = 1,
parameter msb = 0)
(input wire clk, input wire reset,
input wire [width-1:0] s, output reg [width-1:0] s_out);

And here is the related schematic design from CircuitLab. Note that the serial in input is configured as falling edge clk edge, but the ‘output’ is configured as level-shifted clock edge (on nMOS pMOS).
For a 8 bit shift register, the pins should be mapped as (from left to right):
|–IN |–OUT
^ – CLK
| – s
^ – s_out
This section lists the recommended pins for a 8 bit shift register, from the datasheet.

Calculate the delay.
D = %N dps
%N is the number of registers.
Dps is the delay per stage.

Link to a full log of the problem. This will allow others to see what was happening and what is going on in the chip. The FPGA IP implementation is the model in the linked shop. But the problem is on an actual “real” FPGA that doesn’t use an IP block.


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A shift register is a bit sequence that is shifted from one bit to the next when the active cycle of the shift register is completed. Parallel In Serial Out. This involves placing a resistor in series with a shift register to form a “series and a parallel” circuit. This example shows the use of the full chip-package, as well as the more conventional Xilinx IP Cores. A parallel in series shift register consists of a single bidirectional shift register chain of length N, where N is the width of the port, and a single resistor serially connected from the input side of the Nth stage of the bidirectional shift register to the output side of the first stage. A parallel in series shift register can be implemented using only the reference part for the IP Core.

The shift register is a primitive building block in digital electronics, allowing the transmission of bits or groups of bits parallel to one another. A single bit shift register with a selectable input path is normally referred to as a flip-flop, but the concept of the shift register as a primitive building block makes it very general. In the context of digital circuit design, shift registers are used as a form of clocking circuit, whose output is updated at each positive edge of a clock signal. “Shifting” the input data for each bit through the shift register requires an additional clock cycle, the length of which is indicated by the parameter of the shift register.
The concept of the shift register can be extended to an arbitrary size. An X-bit shift register can be constructed by a chain of N 1-bit shift registers in series, with the output of the N-1-th shift register connected to the input of the first shift register.

For an N-bit shift register to work, all of the (N – 1) shift registers and the resistor between them must be connected in series. This results in only one voltage difference between the input end of the shift register and the output end of the shift register. This means the current is the same going into the first shift register and the last shift register. The resistor serves to provide a slight voltage difference to activate the Nth shift register.
The pulse width of the clock controlling the shift register determines the number of clock cycles used. In practice, the maximum clock frequency is determined by the maximum current that can flow through the resistor.

Some kind of clock signal which controls the shifting of the signals must be provided. A classical shift register relies on a single